View Full Version : Brain Teaser
Nano
March 31st, 2006, 11:11 AM
you pick one cup up then put it down then you repeat this 1000 times with 1000 cups
TheDrizzle
March 31st, 2006, 11:12 AM
NO....theyre in a box
TheDrizzle
March 31st, 2006, 11:13 AM
I win * does handstand *
Nano
March 31st, 2006, 11:14 AM
how could you pick up a box with 1000 cups in it with 1 hand?
TheDrizzle
March 31st, 2006, 11:14 AM
**** you...i did it last night
Nano
March 31st, 2006, 11:15 AM
heres one, how do you get a elephant into a fridge?
TheDrizzle
March 31st, 2006, 11:24 AM
In pieces.......hahahahaha
Nano
March 31st, 2006, 11:27 AM
No, you open the door and put it in.
Nano
March 31st, 2006, 11:42 AM
How do you get a Giraffe into a fridge?
HINT: {Think post 258 they are related.}
TheDrizzle
March 31st, 2006, 11:47 AM
Throw it into the fridge
Leader Desslock
March 31st, 2006, 11:48 AM
(yawn)
At this point, we're supposed to say "open the door and put it in", to set you up for the line "No, silly. You have to take the Elephant out first!" Hilarity ensues.
There's a difference between a grade school joke and a brain teaser.
Raistlin-sama
March 31st, 2006, 11:52 AM
[0;1] and [1;infinity[ which of these two have the highest amount of real numbers within their definition?
Nano
March 31st, 2006, 11:55 AM
your right desslock and im glad you didnt make the mistake and laugh
Gannon
March 31st, 2006, 12:40 PM
Gotta love Google.
VSh
March 31st, 2006, 12:43 PM
Nobody has solved it yet.
Imagine yourself in finale of some TV-show. I don't remember the name, but it was very stupid and it doesn't matter anyway. There are 3 big boxes – left, central and right; one of them contains a luxury car – dream of your life. Showman offers you to select one box and win the car. You point to left one. Your chances to win are 1/3, right?
Right.
But it isn't all. The showmen opens central box, and it's empty. What are your chances to win now?
Something between 1/3 and 1/2 dependence on guile of the showman.
Explanation: if the showman knows the winning box, he always can open the box he knew beforehand that's empty. There is at least one empty box from two remaining, so it doesn’t provide you with any useful information and chances are still 1/3. But if the showman plays "honestly", you chances are 1/2 now.
Next, the showman offers you select another closed box, if you wish. Shouldn't you change your mind and do it? What are your chances in this case?
You should switch to the right box now. Your chances are between 1/2 and 2/3 there.
Take your time to think... Again... Repeat...
Wasn’t it nice? Have a good weekend!
Leader Desslock
March 31st, 2006, 12:56 PM
Could you please explain in very simple terms for idiots like me who don't understand how you can have a 2/3 chance? From the point of view of the contestant, I do not see any possible advantage to switching from one box to the next.
Assuming the showman knew that center box (B) was empty and selected it intentionally, that still leaves it an even chance between A and C. Which is 1 in 2.
Nano
March 31st, 2006, 01:03 PM
Thats what I dont get, I mean how could you have a 2/3 chance I mean the box is opened, its out of the problem there isin't 3 box's left there's 2 left.So its a 50 50 chance.And there isin't at least one empty box there's two emtpy boxe's, but only one of them is part of the problem because you know one of the empty boxe's.
Nano
March 31st, 2006, 01:04 PM
Vsh I think your wrong on this one
TheDrizzle
March 31st, 2006, 01:05 PM
I agree with desslock....i dont see how you cood have any more change with either side....
kittykiller3000
March 31st, 2006, 01:55 PM
heres how it works
the gameshow dude reveld one box that was empty. so only two boxes remain,
some may think that there is now a 50/50 chanse, but do to some math rule that is realy long and as many big words, if you change your box, your chanse will dubble. again, this was on that one espiode of Numbers.
Nano
March 31st, 2006, 02:05 PM
I see, thats the worst riddle I've ever heard, and your spelling is appauling
kittykiller3000
March 31st, 2006, 02:22 PM
I see, thats the worst riddle I've ever heard, and your spelling is appauling
now thats just mean.
Leader Desslock
March 31st, 2006, 02:24 PM
Here's the explanation for those who want to read it in English:
http://math.cofc.edu/kasman/MATHFICT/montyhall.html
I have to agree with the analysis, counter-intuitive as it sounds. I think the reason it's perplexing is that at first, you're judging the odds of your choice, rather than your strategy. The second time, you're judging the odds of your strategy, rather than your choice.
I can explain this difference in plain English if anyone wants to hear it. Interesting. The odds of someone walking in blind after B is revealed are different than the odds of the initial contestant.
your spelling is appauling
Ah, delicious irony.
Nano
March 31st, 2006, 02:57 PM
Alright, it's appalling not appauling, but you can't compare me to that.
kittykiller3000
March 31st, 2006, 03:39 PM
hay, that is getting kinda mean.
Nano
March 31st, 2006, 03:41 PM
I was talking about the spelling man, sorry if I hurt your feelings
kittykiller3000
March 31st, 2006, 07:54 PM
sticks and stones may break my bones, but spelling correntions can kill me.
Nano
April 1st, 2006, 05:17 AM
it's spelt corrections not correntions..........opps dont die
Nano
April 1st, 2006, 06:37 AM
You are stuck in a room with no windows or doors. a solid room. the only things in this room is a mirror and a table. how do you excape?
Holy Knight
April 1st, 2006, 07:11 AM
You break the mirror with the table because it's the window to escape through.
Nano
April 1st, 2006, 07:17 AM
no its solid walls all around, its a play on words
kittykiller3000
April 1st, 2006, 01:44 PM
You break the mirror with the table because it's the window to escape through.
that would just cause 7 years bad luck.
CeLL_288
April 1st, 2006, 04:13 PM
Here's the explanation for those who want to read it in English:
http://math.cofc.edu/kasman/MATHFICT/montyhall.htmlThat's so cool, and makes perfect sense once you read it.
your spelling is appauling:lol: :doh: You just pwned yourself.
Nano
April 1st, 2006, 04:26 PM
Yeah we established that a while ago, try the dam riddle.
kittykiller3000
April 1st, 2006, 09:51 PM
you kill killyourself, and turn into a ghost, and just go outside.
MirKz
April 2nd, 2006, 12:04 AM
I WOULD say seein as though you've said its a 'SOLID' room, there is nothing inside, but solid matter, but you have said that there is a mirror and table in there, which consfuses me LOL
Holy Knight
April 2nd, 2006, 07:20 AM
You are stuck in a room with no windows or doors. a solid room. the only things in this room is a mirror and a table. how do you excape?
Hmm...maybe I'm not in that room? I could be in any other room, because you said that there is only a mirror and a table in it, so it would seem it's empty except for those object...
Nano
April 2nd, 2006, 11:53 AM
no you are in that room
TheDrizzle
April 2nd, 2006, 11:59 AM
Break the 'mirror' with the table. reavealing that the mirror is actually a two sided window....Bam your free! its that easy....
Animematt55
April 2nd, 2006, 12:02 PM
^ no it is a solid room.
this is a tough one...
TheDrizzle
April 2nd, 2006, 12:02 PM
;) well....guess your Fed huh?
unless its a tricked question and you dont escape and you just die of stravation?
Nano
April 2nd, 2006, 12:05 PM
oh and the spelling mistake isin't mine in escape
Animematt55
April 2nd, 2006, 12:06 PM
Are just the walls solid?
use te table and climb though the ceiling? Or use it like a shovel or something and dig out?
Nano
April 2nd, 2006, 12:08 PM
no, I said earlier it's a play on words
Ikari Warrior
April 2nd, 2006, 12:40 PM
Sit on the table and reflect. If that doesn't get you out, at least you did some meditation.
Nano
April 2nd, 2006, 01:24 PM
No! Try harder!
Animematt55
April 2nd, 2006, 01:26 PM
i am not gettign the play on words part.
Nano
April 2nd, 2006, 01:29 PM
Bad luck I guess but I have a new one for you.But you still have to try on the other one as well.
Nano
April 2nd, 2006, 01:35 PM
This is a most unusual paragraph-and so is its companion paragraph that follows. This writing may annoy you until you find out why it is so unusual, for you won't find a solution instantly. But don't go into a tailspin about it, for it isn't that difficult. But you will admit that it is most unusual. This writing looks so ordinary that you might think that nothing is wrong with it. And, in fact, nothing is wrong with it. But it is unusual, and you must ask why. If you study and think about it, you may find out why, but you must do it without any coaching of any kind. No doubt if you work at it for long, it will dawn on you...who knows? So start to study it now, and try your skill at finding out what is so unusual about this writing. If you can do it in half an hour, you may claim an approach to wisdom, but if you can't do it in half an hour...find our solution
Bisu
April 2nd, 2006, 01:36 PM
You are stuck in a room with no windows or doors. a solid room. the only things in this room is a mirror and a table. how do you excape? I think I remember this one:
You look in the mirror and see what you "Saw"; you "Saw" the table in half. Two halves make a "Hole." You then escape through the hole!
Am I right?
Nano
April 2nd, 2006, 01:38 PM
Yes.Very good, be proud of yourself!
Leader Desslock
April 2nd, 2006, 02:04 PM
This is a most unusual paragraph-and so is its companion paragraph that follows. This writing may annoy you until you find out why it is so unusual, for you won't find a solution instantly. But don't go into a tailspin about it, for it isn't that difficult. But you will admit that it is most unusual. This writing looks so ordinary that you might think that nothing is wrong with it. And, in fact, nothing is wrong with it. But it is unusual, and you must ask why. If you study and think about it, you may find out why, but you must do it without any coaching of any kind. No doubt if you work at it for long, it will dawn on you...who knows? So start to study it now, and try your skill at finding out what is so unusual about this writing. If you can do it in half an hour, you may claim an approach to wisdom, but if you can't do it in half an hour...find our solution
A solution is hard to find. You must look for many missing shrubs in a wood, sort of. But a solution is in front of you, to find in what is not found. :)
I do not now call to mind a work writ with a similar gimmick, but it is not imaginary.
Nano
April 2nd, 2006, 02:10 PM
A book was writen just like the paragraph but I don't know who it was by.
Yeah you got it.
TheDrizzle
April 2nd, 2006, 02:13 PM
All those sucked ***......
Old Ape Face
April 2nd, 2006, 03:00 PM
hey i got one, You have two cups one filled with milk, the other filled with water. You take a spoon full of millk from the milk cup, and add it to the water cup. then you stur the water cup, then you take a spoon full of the water milk cup and add it to the pure milk cup. now the question: does cup A (the one that started out as water) have more milk added, or does cup b have more water added to the milk, or is the ratio the same between each cup.
Holy Knight
April 2nd, 2006, 03:28 PM
It would depend on the size of the cup and of the spoon. If either is gargantuan compared to the other, there will evidently be a noticeable change, but for ome reason riddles don't care about and circumvent common sense, so I'll assume that both are around the size that you'd expect from finding in your kitchen.
Now, following the riddle, I would say that, as someone with experience in chemistry, the cup with water in it has a higher ratio of milk added to it than the cup with milk has any water. However, this can go down to the molecular level or I'm completely missing the point of the riddle.
Old Ape Face
April 2nd, 2006, 03:41 PM
you're right the cup of water has more milk in it then the cup with milk has water. becuase the first mix was pure milk, but the second was only partly water to begin with, and to make it a deffinet mix, the water was strud so that it would be even more acurate. and as for the size of the equipment, it wouldn't matter, becuase it would always be the same ratio.
kittykiller3000
April 2nd, 2006, 05:24 PM
i got a cool one
which weighs more, the trains that pass through Grand Central Station in one year, or the trees cut to maks U.S currency in one year.
Old Ape Face
April 2nd, 2006, 05:28 PM
i got a cool one
which weighs more, the trains that pass through Grand Central Station in one year, or the trees cut to maks U.S currency in one year.
well if you include the wieght of the station and the train i would say the train and the station, other then that, the United states Dollar is actually composed of cotton, and is re cycled i believe.
Holy Knight
April 2nd, 2006, 05:32 PM
^That would be more statistical knowledge than a riddle. In any case, if we assume the total mass of every train to pass through the central to be around 100 tons and the number of trains to be able to pass through to be X number, it would not matter how many times they passed through, since it would be the very same train. So in the case of U.S. currency, which is made every year and as demand fluctuates, I would assume the number of trees felled to be higher in mass than the trains, because the currency is always in demand, whereas the trains stay at a fixed rate.
Conclusion: Protect our forests and take the train to save our natural petroleum sources.
Old Ape Face
April 2nd, 2006, 05:36 PM
^That would be more statistical knowledge than a riddle. In any case, if we assume the total mass of every train to pass through the central to be around 100 tons and the number of trains to be able to pass through to be X number, it would not matter how many times they passed through, since it would be the very same train. So in the case of U.S. currency, which is made every year and as demand fluctuates, I would assume the number of trees felled to be higher in mass than the trains, because the currency is always in demand, whereas the trains stay at a fixed rate.
Conclusion: Protect our forests and take the train to save our natural petroleum sources.
the american Dollar is Composed of Cotton fibers, not from papre stock,
Holy Knight
April 2nd, 2006, 05:37 PM
the american Dollar is Composed of Cotton fibers, not from papre stock,
Aye? I did not know that. In any case, I still stand by it being higher in mass since we will not stop cultivating it, whereas we will only add in trains as necessary.
Mint Arden
April 2nd, 2006, 05:48 PM
Hmmm... don't know if this one has been said already...
What can go up a chimney down, but can't go down a chimney up?
Dillzman
April 2nd, 2006, 11:17 PM
what has teeth and holds a monster?
Dillon
Nano
April 3rd, 2006, 04:01 AM
smoke..................
Nano
April 3rd, 2006, 04:02 AM
a pregnant monster
Nano
April 3rd, 2006, 04:03 AM
There are four cages in each corner of a room and four animals in the center of that same room that escaped from their cages. Cage number 1 is blue and has a single word enscribed on the door. Cage number two is red, number three is yellow, and number 4 is green, and sits opposite of the blue cage. The blue cage is the only one with letters encribed on it. The four animals are a horse, a giraffe, a gorilla, and a penguin. Which animal belongs in which cage?
kittykiller3000
April 3rd, 2006, 05:17 AM
for all the people you answerd my riddle, the both waigh the same, becaus no train passes through Grand Central Station. and Mony is in the Cotten fibers like what Yukimura-Sanada said. so it was a trick questen.
Nano
April 3rd, 2006, 05:33 AM
your spelling is very bad.
DarkSchneider
April 3rd, 2006, 06:11 AM
your spelling is very bad.
i agree...
Nano
April 3rd, 2006, 06:17 AM
Should be disqualified for bad spelling.
VSh
April 3rd, 2006, 06:43 AM
hey i got one, You have two cups one filled with milk, the other filled with water. You take a spoon full of millk from the milk cup, and add it to the water cup. then you stur the water cup, then you take a spoon full of the water milk cup and add it to the pure milk cup. now the question: does cup A (the one that started out as water) have more milk added, or does cup b have more water added to the milk, or is the ratio the same between each cup.
Yukimura-Sanada and Holy Knight, you are not right here!
It is the same ratio between cups.
kittykiller3000
April 3rd, 2006, 08:07 AM
your spelling is very bad.
we get that i have bad spelling, get over it.
Old Ape Face
April 3rd, 2006, 08:29 AM
you know it's annoying when people spell wrong, but that's nothing to the amounts of complaining I here from the veiwers. Just get over it, people arn't grammar robots, they're not perfect. Now stay on topic or burney's gona close the thread, and for those who would say, "Fine by me, as long as i don't have to read any more Bda Sepllnig," you'r not helping <_<
kittykiller3000
April 3rd, 2006, 08:45 AM
There are four cages in each corner of a room and four animals in the center of that same room that escaped from their cages. Cage number 1 is blue and has a single word enscribed on the door. Cage number two is red, number three is yellow, and number 4 is green, and sits opposite of the blue cage. The blue cage is the only one with letters encribed on it. The four animals are a horse, a giraffe, a gorilla, and a penguin. Which animal belongs in which cage?
i think that the gorilla is in the blue cage. that's all i know.
Holy Knight
April 3rd, 2006, 09:00 AM
Yukimura-Sanada and Holy Knight, you are not right here!
It is the same ratio between cups.
The same? How's that possible?
Old Ape Face
April 3rd, 2006, 09:08 AM
The same? How's that possible?
i agree, if you put one spoon ful of mill in the water, stur and then take the contence of that into the milk cup there would be less water in the milk cut thenmilk in the water cup. :| actually ysh is right to a piont, becuase even though you add part water part milk to the milk cup, you've removed a small mount of milk from the water cup. however, it is a very small amount. it's not exactly 50% milk 50% water in the spoon. and becuase it's stured it makes the percent of milk in the water in the spoon even less, so it is not the same all the time.
VSh
April 3rd, 2006, 07:10 PM
The same? How's that possible?
Look, this we had in the beginning:
+-------+ +-------+
| | | |
| milk | | water |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
+-------+ +-------+
After all that mixes we have something like this:
+-------+ +-------+
| | | |
| water | <=> | milk |
| | | |
+-------+ +-------+
| | | |
| milk | | water |
| | | |
| | | |
| | | |
| | | |
+-------+ +-------+
Obviously, amount of water in the cup with milk must be exactly the same as amount of milk in the cup with water. More precisely, concentration will be spoon/(cup+spoon).
Old Ape Face
April 3rd, 2006, 07:17 PM
Look, this we had in the beginning:
+-------+ +-------+
| | | |
| milk | | water |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
| | | |
+-------+ +-------+
After all that mixes we have something like this:
+-------+ +-------+
| | | |
| water | <=> | milk |
| | | |
+-------+ +-------+
| | | |
| milk | | water |
| | | |
| | | |
| | | |
| | | |
+-------+ +-------+
Obviously, amount of water in the cup with milk must be exactly the same as amount of milk in the cup with water. More precisely, concentration will be spoon/(cup+spoon).
you miss understood, the info was the you put milk in the water then you sture, Then you take one spoon full of the milk/water, and add that to the milk cup, you would be putting less water into the milk then you would be putting milk into the water cup, becuase part of the second spoon is both water and milk. your not adding a fresh spoon of water to one and a fresh spoon to the other.
Leader Desslock
April 3rd, 2006, 07:19 PM
That still doesn't work. The only way it could work is if you removed a spoonful of water BEFORE you mix in the milk. Once you mix the milk into the water, the resulting mixture is not pure. Thus, when you put a spoonful of it back into the milk, you end up adding less water to the milk than you added milk to water. Thus, the ratios will differ.
Now - if you had two spoons, and you removed one spoonful of liquid from each cup, THEN you dumped each spoon's contents into the opposite container, at that point the ratios would be equal.
Old Ape Face
April 3rd, 2006, 07:21 PM
That still doesn't work. The only way it could work is if you removed a spoonful of water BEFORE you mix in the milk. Once you mix the milk into the water, the resulting mixture is not pure. Thus, when you put a spoonful of it back into the milk, you end up adding less water to the milk than you added milk to water. Thus, the ratios will differ.
Now - if you had two spoons, and you removed one spoonful of liquid from each cup, THEN you dumped each spoon's contents into the opposite container, at that point the ratios would be equal.
exactly my point.
VSh
April 3rd, 2006, 07:40 PM
you miss understood...
I understood you right. It doesn’t matter how you mix your liquids. What’s important, that in the end of the procedure you get cup with cocktail of two: milk and water. From where is the water? – From the 2nd cup. And this deficit of water in the 2nd cup was replaced with exactly the same amount of milk from the 1st cup. Volumes of liquids are the same.
Leader Desslock
April 3rd, 2006, 08:04 PM
The total volume of liquids in each cup is equal. That's obvious; nobody's disputing that. What we're saying is that the ratio of milk to water in one cup is different than the ratio of water to milk in the second cup.
If that's not the case, could you show us the math? Because no matter how I do the problem, I come out with a different ratio.
Ikari Warrior
April 4th, 2006, 05:16 AM
hey i got one, You have two cups one filled with milk, the other filled with water. You take a spoon full of millk from the milk cup, and add it to the water cup. then you stur the water cup, then you take a spoon full of the water milk cup and add it to the pure milk cup. now the question: does cup A (the one that started out as water) have more milk added, or does cup b have more water added to the milk, or is the ratio the same between each cup.
Cup A has more milk added because it was pure milk.
Cup B has less water added because it was the same sized spoon with a water/milk mixture.
The overall volume of the two cups might be the same (dunno, not a chem major), but when you get the water out of cup B, it already has milk in it. It's a spoonful of milk, but it's still there -- this is assuming the mixture is uniform. If the mixture is uniform, more milk was added to the water than water to milk. If the mixture was not uniform, then the amount of milk added is equal to the amount of water added (assuming all the milk sank to the bottom).
kittykiller3000
April 4th, 2006, 08:06 AM
there not the same because some of the milk came back in the milk cup with the water.
Nano
April 4th, 2006, 08:14 AM
isin't anyone going to try my riddle?
Nano
April 4th, 2006, 08:36 AM
First Im going to give the cups value so I can understand it better
so water cup has 5 parts and so does the milk cup so you take 1 from the milk cup and put it in the water cup,now in the water cup the ratio is 5:1 and the milk cup has 4 so you take a tea spoon from the water cup, remembering that the ratio in the tea spoon is 0.5:0.1 and you put it in the milk cup so the ratio in the milk cup would be 4.1:0.5 and the ratio in the water cup would be 4.5:0.9 am i right? even if im not you see that the ratio would change because the two ratio's both add up to ten which is what you had from the start if you do it the way i did.Any way can somone tell me if the way i am looking at it is right please.
So i think the water cup has more milk added which is quite obvious really.
VSh
April 4th, 2006, 09:04 AM
... could you show us the math?..
I thought that diagrams make it more obvious. Actually you do not need any math to solve the riddle.
OK, if you persist.
Suppose Vc is the volume of caps. In the end, both cups contain the same volume Vc of a mix of 2 liquids: milk and water. Suppose that V1m and V1w are volumes of milk and water respectively in the mix in the 1st cup, and V2m and V2w – in the 2nd cup. Now we have Vc=V1m+V1w=V2m+V2w. Volume of every liquid is also Vc – we did not refill and did not drink liquids. So, Vc=V1m+V2m=V1w+V2w. And we get V1w=V2m and V1m=V2w immediately. QED
If you are interested in concentration it should be Vs/(Vc+Vs), where Vs is the volume of the spoon.
DarkSchneider
April 4th, 2006, 11:15 AM
It's the concentration of milk to water / water to milk that we're interested in... not the volume.
VSh
April 5th, 2006, 04:59 AM
It's the concentration of milk to water / water to milk that we're interested in... not the volume.
It is almost the same. Concentration is quotient of volumes.
***
This time is simple one:
You are traveling in an airplane on Northeast all time. What is your destination point?
drgenestarwind
April 5th, 2006, 07:13 PM
thought on milk/water puzzle, since, in the end, the volumes of the two glasses are equal right. Volume(initial/milk)=Volume(initial/water)
Volume(initial/milk)+Volume(initial/water)=Volume(final/milk)=Volume(final/water)
so, since the two voumes are equal, what you added to the first you took from the second, thus the exchanges must be equal.
Leader Desslock
April 5th, 2006, 07:42 PM
You are traveling in an airplane on Northeast all time. What is your destination point?
The north pole. You can't run out of East, but you can run out of North, and that's where you'll be when you do.
VSh
April 6th, 2006, 04:37 AM
The north pole.You are right.
DarkSchneider
April 6th, 2006, 10:42 AM
heres how it works
the gameshow dude reveld one box that was empty. so only two boxes remain,
some may think that there is now a 50/50 chanse, but do to some math rule that is realy long and as many big words, if you change your box, your chanse will dubble. again, this was on that one espiode of Numbers.
Here's a link with a java game of this...
http://people.hofstra.edu/staff/steven_r_costenoble/MontyHall/MontyHallSim.html
I still think it's 50% chance.
Holy Knight
April 6th, 2006, 10:50 AM
Here's a link with a java game of this...
http://people.hofstra.edu/staff/steven_r_costenoble/MontyHall/MontyHallSim.html
I still think it's 50% chance.
No, it's 2/3. I worked it out myself after thinking about it for a bit. Here's what, consider this scenario: we have a guy that is a contestant and will always switch choices. This means that if the prize is in door A, the only way for him to lose is to choose door A, since he always switches. Not switching only gives you 1/3 winning chances, whereas always switching gives you 2/3, because then the two bad choices will become good ones. Think about it.
DarkSchneider
April 6th, 2006, 10:58 AM
Too much thought process going into that one. I played the java game and was at 50% for both staying and switching... after 32 attempts. I'll stick with putting my dollar in for a quick pick on the mega mill...
Caine
April 6th, 2006, 12:38 PM
No, it's 2/3. I worked it out myself after thinking about it for a bit. Here's what, consider this scenario: we have a guy that is a contestant and will always switch choices. This means that if the prize is in door A, the only way for him to lose is to choose door A, since he always switches. Not switching only gives you 1/3 winning chances, whereas always switching gives you 2/3, because then the two bad choices will become good ones. Think about it.
I have never heard this problem worded well. The probablity of winning when you use the switching strategy is better, but the actual probability isn't different. If you come in and simply roll a die to decide which one you pick, then flip a coin to decide which one of the remaining 2 to pick, it is equal. It is only when the strategy is viewed as a whole that the advantage materializes.
[0;1] and [1;infinity[ which of these two have the highest amount of real numbers within their definition?
Bah, more math. assuming you meant [1;infinity], then they have equal amounts of Real Numbers in them. I'm assuming you know the math behind this, and so I'm wondering if you know where I can find the proof that the set of Integers has fewer elements (I know that's incorrect terminology) than the set of Rationals.
VSh
April 6th, 2006, 05:03 PM
I'm wondering if you know where I can find the proof that the set of Integers has fewer elements (I know that's incorrect terminology) than the set of Rationals.Nobody knows, because it does not exist. They are both countable (http://en.wikipedia.org/wiki/Countable).
dreamer
April 6th, 2006, 05:24 PM
I have never heard this problem worded well. The probablity of winning when you use the switching strategy is better, but the actual probability isn't different. If you come in and simply roll a die to decide which one you pick, then flip a coin to decide which one of the remaining 2 to pick, it is equal. It is only when the strategy is viewed as a whole that the advantage materializes.
But how can you separate the strategy and the probability of this game? IF, and only if, you enter the game AFTER one of the 3 was revealed to be wrong, THEN the probability of choosing either one of the remaining two can be 50%. But since you enter the game FROM THE BEGINNING, you cannot separate the two times of choosing. Because if you do, and believe the second time your chance will be 50/50 whether you switch or not, so you stick with what you chose before, you'll realize you only have 1/3 of the chance of winning.
What I want to say is, I know you know that "switch" is a better choice, but I just don't understand how can something favours you, when the probability is the same, 50/50? The probability must be different, because one way it favours you, one way it doesn't.
Try this out yourself, with cards, or 3 cups and a candy. After several times of trials, you'll realize the chance is NOT 50/50.
drgenestarwind
April 6th, 2006, 06:18 PM
Caine, every rational can be expressed as some integer X over some other integer Y. both sets themselves are infinite. but below some number N (excluding negatives) there are more rationals than integers.
Mint Arden
April 6th, 2006, 10:15 PM
smoke..................
If that was a guess to my riddle, that's not the answer. X3
VSh
April 7th, 2006, 09:50 AM
... there are more rationals than integers.
You are not right. They have the same cardinality. Read that topic in Wikipedia I mentioned.
Caine
April 8th, 2006, 10:48 AM
You are not right. They have the same cardinality. Read that topic in Wikipedia I mentioned.
more is a bad choice of words. they have the same cardinality, but "more" is such an imprecise term that I should be shot for even thinking about using it in this context. It may in fact be true, but that depends on the definition of more that is used and how skilled at semantics the people on wither side of the argument are. I should have thought my post through before posting it. i also meant that they were the same, i don't know why i said different, I'm really out of it.
dreamer, you do so by being completely random. If you you seperate the choices (such as by determining each choice with a coin flip or dice roll), then it does come out 50/50. this brings up the interesting ideas about knowledge affecting reality and all that
Why do we bother mixing semantics and math? Didn't we learn from the Greeks?
dreamer
April 8th, 2006, 05:03 PM
dreamer, you do so by being completely random. If you you seperate the choices (such as by determining each choice with a coin flip or dice roll), then it does come out 50/50. this brings up the interesting ideas about knowledge affecting reality and all that.
Did I? I just don't see how you can separate the choices. The reason why the second choice is not 50/50 but 1:2 is that after your first choice, the person can only choose to reveal the "wrong" one of the remaining two. If the remaining two are both wrong, which is only 1/3 of the chance, then he can choose whichever one he pleases to reveal. But if you already chose a wrong one in your first choice (which has a 2/3 chance), then you had left him no choice but to reveal the only other wrong answer. The second choice, in reality, is NOT a separate second choice, but is just an extention of the first choice.
kittykiller3000
April 11th, 2006, 05:28 AM
try to connect all the dots with out going over the line you just made
. . .
. . .
. . .
just put some numbers were you go next
Nano
April 11th, 2006, 05:31 AM
thats so lame.
just post a picture of it done on apeice of paper
DarkSchneider
April 11th, 2006, 05:55 AM
try to connect all the dots with out going over the line you just made
. . .
. . .
. . .
just put some numbers were you go next
Going by your description, don't you just have to connect the dots in a spiral, 'z' or 's' pattern??? Or are there supposed to be like 4 small boxes when you're done?
Nano
April 11th, 2006, 06:06 AM
no he is an idiot, your given a set amount of lines to do it in but he hasn't told uss how many...
DarkSchneider
April 11th, 2006, 06:09 AM
well he said you can't cross over the lines, so this isn't the one where you make a star pattern.
Holy Knight
April 11th, 2006, 06:21 AM
Err...it's easy:
._._.
|._._.
._._.|
Just make an "s" form over the dots...
Nano
April 11th, 2006, 06:22 AM
it goes outside of the box thats all i know and all i care to know, i could do it but i don't like the puzzle so i won't. it goes 2 1 4 7 5 3 6 9 8. all in one big line
1 2 3
4 5 6
7 8 9
i changed my mind..................
and you are right it is he that has got it wrong its with a set amount of lines and they do go outside of the box and they do cross.
VSh
April 12th, 2006, 05:11 AM
try to connect all the dots with out going over the line you just made
. . .
. . .
. . .
just put some numbers were you go next
I think you wanted this:
*-*-*-
|\ /
* * *
| X
* * *
|/
Mint Arden
April 16th, 2006, 01:07 AM
Okay... it's been awhile. The answers an umbrella!! XD
upjumpstheboggi
April 16th, 2006, 06:52 PM
I got one!
There were 12 pears hanging high and 11 cowboys came riding by. Each took one, how many pears are left?
kittykiller3000
April 17th, 2006, 08:06 AM
i think it's two
Nano
April 17th, 2006, 08:09 AM
I think it's the pears that took one so the answer is 12.
upjumpstheboggi
April 17th, 2006, 09:55 PM
No it's 11.
VSh
April 18th, 2006, 07:23 AM
Here is a logic problem I got on an interview in one big well-known company. In my opinion, it was too simple for engineering position.
There are 3 closed boxes (again!). There are labels, one on each box: "2 white balls" on first box, "2 black balls" on second box, and "1 white ball and 1 black ball" on third box. All labels are true, but on wrong boxes. You may extract only one ball from only one box by your choice. After that you need to put the labels on right boxes. Your actions?..
Leader Desslock
April 18th, 2006, 02:24 PM
^ Here's the hint, for anyone who doesn't have the answer: The secret lies in the phrase "All labels are true, but on wrong boxes".
master terrence
April 18th, 2006, 04:15 PM
Here is a logic problem I got on an interview in one big well-known company. In my opinion, it was too simple for engineering position.
There are 3 closed boxes (again!). There are labels, one on each box: "2 white balls" on first box, "2 black balls" on second box, and "1 white ball and 1 black ball" on third box. All labels are true, but on wrong boxes. You may extract only one ball from only one box by your choice. After that you need to put the labels on right boxes. Your actions?..
well if all the boxes are wrong then there should be no problem
If I get white from a white and black label I know I should change the label to white and white... so on so forth, am I wrong?
Know I know there can only be one white left, and if I pick a white I should label that box white and black... and the last one is black and black.
VSh
April 21st, 2006, 09:54 AM
Good. Now, for this weekend, a simple problem from the same interview:
They give you sheet of paper with 10 statements written on it:
There is 1 false statement written here.
There are 2 false statements written here.
There are 3 false statements written here.
There are 4 false statements written here.
There are 5 false statements written here.
There are 6 false statements written here.
There are 7 false statements written here.
There are 8 false statements written here.
There are 9 false statements written here.
There are 10 false statements written here.
Is there something true here?
Leader Desslock
April 21st, 2006, 10:02 AM
Yes. There are nine false statements written there: Lines 1 through 8 and line 10 are all false, which makes the 9th line "there are 9 false statements written here" a true statement.
VSh
April 21st, 2006, 10:51 AM
Yes. There are nine false statements written there: Lines 1 through 8 and line 10 are all false, which makes the 9th line "there are 9 false statements written here" a true statement.
Right. You knew.
Now they give you another sheet with:
There is at least 1 false statement written here.
There are at least 2 false statements written here.
There are at least 3 false statements written here.
.
.
.
There are at least N false statements written here.
What about this?
Holy Knight
April 21st, 2006, 10:55 AM
Then there are N-1 false statements.
Leader Desslock
April 21st, 2006, 11:02 AM
^ Right. The kicker for this one is that the reader is meant to read the statements and evaluate them one at a time. So the first time the reader gets to statement #9 (or N-1) reading them in order, it's false. It's only when the reader goes to statement N that statement N-1 becomes true.
VSh
April 21st, 2006, 11:07 AM
^, ^^ You are cought. It is not right. Think better.
Holy Knight
April 21st, 2006, 11:41 AM
^, ^^ You are cought. It is not right. Think better.
Hmm...Then there are N wrong statements? This goes into infinity, therefore even N is wrong...
drgenestarwind
April 21st, 2006, 09:05 PM
here's a teaser. how many prime numbers are there? finite or infinite? prove your answer.
Holy Knight
April 22nd, 2006, 06:28 AM
here's a teaser. how many prime numbers are there? finite or infinite? prove your answer.
Infinite. The latest, and biggest, prime number found has around 153 million digits (if I recall correctly). If a prime number can be that big, then there surely has to be another, bigger prime number.
Nano
April 22nd, 2006, 09:33 AM
he wants you to do it in algerbra,its not enough to just say it or give lots of examples.
Leader Desslock
April 22nd, 2006, 10:42 AM
I think there used to be an AN member who used to be pretty good at this sort of thing. I forget his name... Eucalyptus, Eucantouchthis, Eucl... something. I dunno. I bet he could do this.
VSh
April 22nd, 2006, 11:01 AM
how many prime numbers are there? finite or infinite?
Infinite. I have got a wonderful proof of it, but I am too lazy to provide it here.
drgenestarwind
April 22nd, 2006, 06:42 PM
false HK, the largest known prime number (disovered december 2005) has 9.2 million digits, no big enough to claim any EFF prizes.
Holy Knight
April 22nd, 2006, 07:12 PM
false HK, the largest known prime number (disovered december 2005) has 9.2 million digits, no big enough to claim any EFF prizes.
Ah yes, thanks for the correction. I saw the article in a science magazine, so time must have distorted the number.
VSh
April 24th, 2006, 05:20 AM
There was no right answer on my riddle yet. Have you given up?
Hint: pay attention on "at least".
kittykiller3000
April 24th, 2006, 08:06 AM
i have another bad pun.
What is a light year.
Nano
April 25th, 2006, 06:20 AM
puns?
A good pun is its own reword.
herewegoagain
April 25th, 2006, 08:49 AM
Why ban someone after a month of posting up to 100 messages?
herewegoagain
April 25th, 2006, 08:50 AM
Hint: There is no answer.
VidelCoolGirl
April 25th, 2006, 09:35 AM
Q. Why pay attention to someone who flames all the threads?
A. DONT!
VSh
April 27th, 2006, 07:53 AM
No right answer for a week! I guess it was too difficult.
They give you sheet with:
There is at least 1 false statement written here.
There are at least 2 false statements written here.
There are at least 3 false statements written here.
.
.
.
There are at least N false statements written here.
Is there something true here?
All statements cannot be false, because it would contradict to falsity of every statement (1st, for example). So there must be something true here.
The last statement cannot be true, because it would contradict to itself. So the last statement must be false and 1st must be true. The same things for (N-1)th and 2nd statements, (N-2)th and 3rd, etc, until they meet in the middle of the list.
Now if N is even, they meet indeed and 1st half of the list contains true statements and 2nd half contains false statements. But if N is odd, there is one statement exactly in the middle that cannot be true and cannot be false. Too bad, there is no solution in this case.
Damn, I like paradoxes!
kittykiller3000
April 27th, 2006, 08:07 AM
i still have a brain teaser you Know
TheDrizzle
April 27th, 2006, 08:16 AM
what is it??? tell us
kittykiller3000
April 28th, 2006, 05:24 AM
if no one will even try,
it's 12 months with less calariors.
VSh
April 29th, 2006, 03:29 PM
I remembered a good one:
Why mirrors swap left and right, but do not swap top and bottom?
Bisu
April 29th, 2006, 03:43 PM
If memory serves me correct: Because mirrors do not swap left and right, they swap in and out.
Am I right?
Mint Arden
April 30th, 2006, 01:02 AM
Mirrors make your left hand your right hand in the mirror image. And make it REALLY confusing to manouever delicately by looking into one.
VSh
May 1st, 2006, 10:13 AM
If memory serves me correct: Because mirrors do not swap left and right, they swap in and out.
I did not catch. Does the verb "swap" make some idioms with "in" and "out"? My dictionary has nothing about it.
Mirrors make your left hand your right hand in the mirror image. And make it REALLY confusing to manouever delicately by looking into one.
OK, without hands. Write two words on sheet of paper, first from the left to the right, and second from the top to the bottom. Now look at the sheet throw a mirror. Horizontally written word swaps sides, and vertically does not. What do first word better (or worse) than second?
Ikari Warrior
May 1st, 2006, 10:26 AM
I remembered a good one:
Why mirrors swap left and right, but do not swap top and bottom?
All mirrors are installed upside-down so that nothing is upside down :P
Rain
May 2nd, 2006, 11:21 AM
All mirrors are installed upside-down so that nothing is upside down :P
Wait, what?!? I don't get it.
VSh
May 16th, 2006, 06:58 AM
I like this thread. So, let's revive.
Why mirrors swap left and right, but do not swap top and bottom?
Simply because you identify objects with their mirror images this way.
kittykiller3000
May 17th, 2006, 08:27 AM
this is wores than the milk/water riddle that we had a while back
VSh
May 23rd, 2006, 11:09 AM
OK, something easy for training
How many pets I have if
all of them except 2 are dogs,
all of them except 2 are cats, and
all of them except 2 are parrots?
Leader Desslock
May 23rd, 2006, 11:16 AM
Three: a dog, a cat and a parrot.
VSh
May 26th, 2006, 07:08 AM
Every day it is more difficult to find some good riddle with answer that won't appear in first strings of google search.
Here is one:
Continue this letter sequence in both directions:
...JASON...
Leader Desslock
May 26th, 2006, 09:26 AM
Every day it is more difficult to find some good riddle with answer that won't appear in first strings of google search.
I didn't use google. The answer just hit me when I read it. ^_^
drgenestarwind
May 26th, 2006, 07:06 PM
J,f,m,a,m,j...jason...d
VSh
May 29th, 2006, 06:56 AM
J,f,m,a,m,j...jason...d
Very good.
kittykiller3000
May 31st, 2006, 08:55 PM
in south america/ a woman was being chased by a gang of bandits. she had escaped with two solid gold balls,(he he he) and the bandits would kill her to take the balls.(he he he)She came to a bridge over a deep ravine. the bridge was 100 feet long. there was a notice on the bridge thet said"max-weight 112lbs." the notice was 100% accurate. she weighed 100lbs and each of the balls weighed 10 lbs. there was no thime to leave one ball behind and com back of it. and yet she managed to get acroos the bridg safely with both balls(he he he). HOW?????
Haro!
May 31st, 2006, 10:23 PM
Simple. Because the max wieght simply would refer to the bridge's elastic region and doesn't fail until another 10 lbs.
Leader Desslock
June 1st, 2006, 03:33 AM
I suppose the "bowling" approach wouldn't work? Depending on the style of the bridge, she could roll each of the ball across the bridge ahead of herself. They'd get there far faster than if she had to run back for one of them. The moment they hit the other side of the bridge, she could run across herself.
Then again, since the sign would presumably refer to "the max weight supportable in a single spot on the bridge" and not "the total weight supported by the entire bridge", she could just start them rolling and start running after them once they'd gotten, say, 20 feet ahead of her. She would just need to make sure she didn't catch up to them.
Of course, this wouldn't work so well with a rope bridge...
On a side note, would you really trust a 100-foot long span that could only support 112 lbs?
kittykiller3000
June 1st, 2006, 07:20 AM
the answer is more obvious than rolling the balls.
Leader Desslock
June 1st, 2006, 07:44 AM
If the "real" answer is juggling the balls while she crosses, I think you're misunderstanding basic physics.
kittykiller3000
June 1st, 2006, 07:53 AM
but the answer is juggling.
Leader Desslock
June 1st, 2006, 08:11 AM
Um, YOUR answer might be juggling, but I assure you that will not work. Are you forgetting that the amount of force required to toss one of the balls up in the air will be added to her weight during her upswing? So will the amount of force required for her to stop the ball's motion as she catches it. If you calculate that out, I bet she exceeds 112 pounds. ^_^
kittykiller3000
June 1st, 2006, 09:08 AM
but she'll toss it in the air as soon as it lands in her hand.
drgenestarwind
June 1st, 2006, 07:11 PM
right, the added force of tossing a ball up, and absorbing the force of a falling ball create a percieved increase in weight, for every action there is an equal but opposite reaction.
Caine
June 1st, 2006, 07:18 PM
what if she doesn't catch the ball, but simply hits it? if she never allows the balls to actually be added as a downward force, but as a more outward force, plus she never hits both at the same time, could that work?
Leader Desslock
June 1st, 2006, 08:15 PM
^ Ever try to "bat" a ten-pound gold ball? ^_^ Nice try, but her upswing would still be added as a downward force (stand on a scale and try this), as would some of the force from the impact.
Ultimately, let's assume she has a 1-meter arc on the balls she's juggling, from the low point of where each ball is caught and the high point where it begins falling. Nothing in this world is going to alter the fact that X amount of force is required to move a ten-pound ball one meter upwards. If the force is gradual or sudden, the same amount of force is required to move the ball. Whatever force she directs up is going to push down on her body. Whatever downward force she stops by catching balls will be absorbed by her body and added to her weight, along with the weight of the ball.
This is one of those things that works well on paper, but you might want to take a look at the physics. Bowling will work; I don't believe juggling will, in any form.
She could put the balls in a backpack, tie a long rope to the pack, walk across the bridge then drag the backpack across behind her. That would work. She could improvise a makeshift sling and try to fling one of the balls across. Lots of things might work.
Jabberwock
June 1st, 2006, 10:49 PM
I say she just stands on the end of the bridge and lets it break as she swings across to relative safety.
Now, you have the chasm crossed, the bandits without a venue to follow directly, and your gold balls. Plus, if they're chasing you, you need to make a dramatic move like in the movies. And there ain't anything more dramatic than bridge-swinging.
...except maybe boulder outrunning.
Caine
June 2nd, 2006, 12:24 PM
^^bowling only works if it has good enough sides or if you are a really accurate bowler. The sling and backpack idea relies on having materials (and to some degree, time) There is no practical way.
And there ain't anything more dramatic than bridge-swinging.
...except maybe boulder outrunning.
what about SNAKES ON A PLANE?
drgenestarwind
June 2nd, 2006, 09:01 PM
how 'bout a shotput, whats the best range for a 12 lb ball?
Leader Desslock
June 2nd, 2006, 09:07 PM
^ A womens' shot put is just over 8 pounds, and the world record is just over 22 meters. The woman in the puzzle seems pretty small at 100 lbs, so the odds of her even getting a 10 lb ball past the center of a 100 foot long bridge are... slim, I'd say.
Haro!
June 2nd, 2006, 09:24 PM
I think my explanation was best and lets just leave it at that...
VSh
June 5th, 2006, 06:41 AM
she managed to get acroos the bridg safely with both balls(he he he).
This girl is really incredible. She could do it if only:
She is strong enough to toss the ball at least till the middle of the bridge.
She is fast enough to get to the middle together with that ball.
She has long enough arms to catch that ball and doesn't exceed the bridge weight limit.
And she is really good circus actor so she could coordinate those things all together with her running.
VSh
June 7th, 2006, 09:20 AM
I remember one nice classic riddle.
Three guys – Al, Bob, and Cy – are riding a train. Al brought 5 bottles of beer, Bob – 3 bottles, and Cy brought $8. During the journey they drank all beer equally. In the end Cy gave his $8 to other guys for the beer. How Al and Bob should honestly divide the money between them?
Caine
June 7th, 2006, 11:51 AM
^not another math problem!
$5 and $3 isn't the answer you want, but its the easiest one to give. since they're drunk anyway, nobody cares if its actually the most fair way.
If i remember this type correctly, since Bob only gives 1/3 of a bottle and Al gives 7/3, Bob gets one dollar and Al gets seven.
Leader Desslock
June 7th, 2006, 12:04 PM
My answer, since it doesn't say that all the beer was drunk, would be to say Al and Bob split the money equally, because Cy bought one bottle of beer off each of them (at $4 a bottle!). That left Al with 4 bottles and Bob with 2 bottles. After the purchase, Cy has two bottles. They all drink two bottles (thus drinking equally), and Al goes home with an extra two bottles unopened.
VSh
June 7th, 2006, 12:20 PM
^ During the journey they drank all beer equally.
not another math problem!
No way! This world is suffused with (suffered from) math.
P.S. Yes $7+$1 is right answer.
blackknight
June 7th, 2006, 02:13 PM
I'll bet no one will get this one.
If I have three apples, how many apples do I have?
kittykiller3000
June 7th, 2006, 09:02 PM
three?????
VSh
June 12th, 2006, 06:34 AM
Zero.............
kittykiller3000
June 20th, 2006, 04:30 PM
i got one
What can humans see that god can't.
Holy Knight
June 20th, 2006, 04:33 PM
i got one
What can humans see that god can't.
The tip of their nose.
Rain
June 20th, 2006, 04:35 PM
Why can't God see the tip of His nose? o.o
I got a riddle (it's pretty old but whatever):
"What is greater than God,
More evil than the devil,
The poor have it,
The rich need it,
And if you eat it, you'll die?"
kittykiller3000
June 20th, 2006, 04:50 PM
nothing,
and nose is not the anwser to my riddle
Leader Desslock
June 20th, 2006, 05:34 PM
^ Humans can see their belly buttons. God, not having a mother, presumably can't.
kittykiller3000
June 20th, 2006, 06:29 PM
that works, but i was looking for a different anwser
Caine
June 20th, 2006, 07:09 PM
to the God one, how about their own death? God cannot see his death as He can't die, only himans can see their own deaths?
Rain
June 21st, 2006, 01:39 PM
to the God one, how about their own death? God cannot see his death as He can't die, only himans can see their own deaths?
WTF? ... We can't "see" our own deaths if by "seeing", you mean, "foreseeing".
kittykiller3000
June 21st, 2006, 01:53 PM
well my answer was an "Equal" or a "Superior".
Caine
June 21st, 2006, 03:02 PM
^hmmm, I suppose not, though quite a few people can't recognize one.
^^no, I meant seeing as in seeing it with our eyes. We see the events of our death (from our own point of view of course) as they happen. God, with no death, cannot see the events of his death because he doesn't have one.
kittykiller3000
June 23rd, 2006, 11:36 AM
^hmmm, I suppose not, though quite a few people can't recognize one.
^^no, I meant seeing as in seeing it with our eyes. We see the events of our death (from our own point of view of course) as they happen. God, with no death, cannot see the events of his death because he doesn't have one.
but isn't god waching eath, so wouldn't god see death as munch as us.
Caine
June 23rd, 2006, 11:45 AM
not his own. he would see my death, maybe even from my perspective, but he could not die and thus he couldn't see his own death
VSh
June 28th, 2006, 06:18 AM
I wanted to post this riddle for a long time but was afraid the problem could be very difficult. Now I see there are enough people that like astronomy. So, astronomical riddle:
Imagine yourself as an astronaut on the Moon. You are in a space suit outside on the Moon surface for a picnic to see the Earth's rising. The event is undoubtedly very happy for you...
Wait a minute! Something's wrong here! What and where?
Caine
June 28th, 2006, 09:04 AM
Don't we only see one face of the moon? I believe there shouldn't be an "earthrise" from the moon.
kittykiller3000
June 28th, 2006, 09:07 AM
and how can you eat on the with a spacesute on?
drgenestarwind
June 28th, 2006, 08:00 PM
because to anyone on the moon the position of the earth never changes. we always see the same face of the moon right? so as a corrolary the earth stays in the same (relative) spot. this is because of the rotation and revolution of the moon.
Powatanner
June 28th, 2006, 08:42 PM
Each child in a family has at least 2 brothers and 2 sisters. What is the smallest number of children the family might have?
kittykiller3000
June 29th, 2006, 03:33 AM
5
<filler>
VSh
June 29th, 2006, 07:10 AM
I believe there shouldn't be an "earthrise" from the moon.... the earth stays in the same (relative) spot.Not so fast!
Interesting that in 1967 in USSR was published this post stamp:
http://img114.imageshack.us/img114/7954/pic0321pr.jpg
The title is "On the Moon."
And this is the real painting of cosmonaut A.Leonov:
http://img267.imageshack.us/img267/4631/3081vr.jpg
Look at the black detail of the landscape in bottom right corner of the post stamp. It hides second part of the title: "The Earth's rising." They found the mistake too late, and "rescued" the post stamp by later overprinting above ready sheets. US made the similar mistake too:
http://img103.imageshack.us/img103/7492/pic0343te.jpg
In the place "Apollo-11" was set on the Moon the Earth was almost in the zenith.
You thought in the right direction, but it isn't the entire true. You know me, if I said that it is a difficult problem, then it isn't so simple. Are you sure you're right?
drgenestarwind
June 29th, 2006, 09:19 PM
the moon orbits around the earth and turns about its axis at the same angular velocity, the same face of the moon always faces earth so to us the moon is static.
VSh
July 1st, 2006, 07:51 PM
the moon orbits around the earth and turns about its axis at the same angular velocity, the same face of the moon always faces earth so to us the moon is static.
There is nothing ideal in this world.
Small hint:
have you heard about libration?
drgenestarwind
July 1st, 2006, 09:13 PM
everything about the riddle seems to be okay except for the earth rise thing. i probably understand it but cant express it in words or i dont know what im missing in my explination, either someone else take it, or i want to hear the answer.
kittykiller3000
July 2nd, 2006, 01:11 PM
but isn't there different vases of the moon. soo wouldn't you see the earth rising when it goes from one vase to anouther
Leader Desslock
July 2nd, 2006, 01:58 PM
but isn't there different vases of the moon. soo wouldn't you see the earth rising when it goes from one vase to anouther
That'd be "phase" and it has nothing to do with the rotation of the moon relative to the Earth. Moon phases are caused by the angle of the sun relative to the moon as it revolves around the Earth. When the moon is at a 90 deg angle between the Earth and the Sun, we see a half moon on Earth; when the moon is at 180 degrees, we see a full moon. During all these times, the same side of the moon is still facing the Earth, however. Or - from the perspective of an observer on the moon, the Earth's in the same postition in the sky.
Regarding libration: would that really be an issue for folks at a lunar picnic? They'd have to wait about two weeks for the moon to go from one extreme to the next, and even then the change would only be a matter of a few degrees. At best, the Earth would shift in apparent position from just below the horizon to just above it. So unless the picnic is a fortnight-long gathering of nitpickers, I don't see the relevance.
In terms of lunar real estate, however - spots which offer such an "Earthward" view would be the premium locations, I'd think. The novelty factor alone would drive up the demand for such lots. Sure, there's the issue of reception, but it's nothing that couldn't be solved just like Cable TV here on Earth.
VSh
July 5th, 2006, 04:22 PM
Obviously, who ordered to censure words “The Earth’s rising” thought similar. But it isn’t entire true. Let’s see. Wikipedia article (http://en.wikipedia.org/wiki/Libration) has nice animation of libration, in other things it’s primitive and doesn’t have even numbers, exclude 59% of visible moon surface. So, on 41% the Earth can’t be seen at all, on other 41% the Earth can be seen always. What about left 18%?
To get some meat you need astronomic dictionary. Latitude libration is 6°40′ and is a consequence of difference in planes of the Moon orbit and the Moon equator. Period of this libration is draconic month (27d 5h 5m 36s). Longitude libration is 7°54′ and produced by eccentricity of the Moon orbit. Period of this libration is anomalistic month (27d 13h 18m 33s). Those months aren’t equal and the Earth “moves” on complex trajectory, something like Lissajous curve (http://en.wikipedia.org/wiki/Lissajous):
http://img346.imageshack.us/img346/2006/librations9cl.gif
This isn’t square but rectangle on sphere. Orientation is dependent on moon latitude and longitude of the place. One side is 13°20′ (6°40′x2), another is 15°48′ (7°54′x2), with diagonal ~20°. Visible diameter of the Earth on the Moon surface is ~2°. So the Earth “moves” 8-10 diameters - not bad! Therefore Earth risings will take 2 days in the best case. Not so fast, but enough to be attractive.
I’d build some hotel or Luna park in middle latitudes near visible border on the Moon.
P.S. I have to thank P.Makovetsky for this problem and excellent “Look in the Root!” book.
VSh
July 15th, 2006, 12:37 PM
Hope, you are not scared. Actually that Moon riddle was not so difficult.
This time very simple but also "astronomical" riddle.
Continue this letter sequence to both directions:
...SUN...
Leader Desslock
July 15th, 2006, 12:45 PM
Mvemj- Sun - P
...and because it's relevant...
THE PLANETS SONG
----------------
YAKKO: It's time to tour the planets that make up our Solar System! C'mon!
The closest to the Sun is the planet Mercury;
Next the shrouded planet Venus is as cloudy as can be.
The Earth is next, we call it home; let's hope it stays that way.
And then there's Mars, it's really red, what more can I say?
The gassy planet Jupiter's as big as planets come;
Then there's Saturn with its mighty rings made up of tiny crumbs.
We travel on to Neptune, that's a gassy, greasy ball;
And cold and tiny Pluto is the furthest one of all!
Well, there you go -- that's our solar system!
WAKKO: You forgot Uranus.
YAKKO: Goodnight, everybody!!
VidelCoolGirl
July 15th, 2006, 12:51 PM
Mvemj- Sun - P
...and because it's relevant...
THE PLANETS SONG
----------------
YAKKO: It's time to tour the planets that make up our Solar System! C'mon!
The closest to the Sun is the planet Mercury;
Next the shrouded planet Venus is as cloudy as can be.
The Earth is next, we call it home; let's hope it stays that way.
And then there's Mars, it's really red, what more can I say?
The gassy planet Jupiter's as big as planets come;
Then there's Saturn with its mighty rings made up of tiny crumbs.
We travel on to Neptune, that's a gassy, greasy ball;
And cold and tiny Pluto is the furthest one of all!
Well, there you go -- that's our solar system!
WAKKO: You forgot Uranus.
YAKKO: Goodnight, everybody!!
:lol: You Win the prize Leader.
VSh
July 15th, 2006, 01:02 PM
Mvemj- Sun - P
You are fast!
It seems one letter should be added to the sequence.
VSh
July 18th, 2006, 09:49 AM
Another "moon" riddle
By guinness highest man's jump is 2.45m (8ft 0.5in). How high would it be on the Moon?
Note: Gravitation on the Moon is 6 times weaker.
EDIT: Guinness book redesigned its site and removed almost everything interesting. So, now it's by Wikipedia: http://en.wikipedia.org/wiki/High_jump.
VSh
October 15th, 2007, 05:30 AM
Nobody answered it yet?
Hint: It will be multiplication by 6, but what? What are jumpers lifting exactly?
DysPerDis
October 15th, 2007, 10:17 AM
I assume the answer is 14.7 m, seeing as the jumper was lifting his own body weight, which weighs 1/6th as much on the moon...
Although, that's assuming that the question is really as straightforward as it appears.
Broand
October 15th, 2007, 10:29 AM
The real question however is why did you revive this thread?
Caine
October 15th, 2007, 12:30 PM
do you want air resistance or not?
VSh
October 16th, 2007, 06:23 AM
do you want air resistance or not?
Can you approximate the impact of air resistance? I think that is should be only a few centimeters. I'm not asking for exact answer, only for a good approximation.
I assume the answer is 14.7 m, seeing as the jumper was lifting his own body weight, which weighs 1/6th as much on the moon...
It could be right for a frog, probably, but not for a man. Why are they developing complicated techniques like Fosbury Flop (http://en.wikipedia.org/wiki/Fosbury_flop)?
The method used is to sprint diagonally towards the bar, jump off the outside foot, then curve and leap head-first, back-downwards over the bar in a rolling motion keeping as much of the body as possible below the bar. When high jumpers perform this jump, they bend their body in such a way that it is possible for the athlete to clear the bar while his or her center of mass does not. In fact, the body's center of mass can be kept as much as 20 cm under the pole.
vBulletin® v3.8.2, Copyright ©2000-2012, Jelsoft Enterprises Ltd.